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The temperature of an ideal gas is incre...

The temperature of an ideal gas is increased from 120 K to 480 K. If at 120 K the root mean square velocity of the gas molecules is v, at 480 K it becomes

A

`4v_(rms)`

B

`2v_(rms)`

C

`(2v_(rms))/(2)`

D

`(v_(rms))/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(v_(rms_(2)))/(v_(rms_(1)))=sqrt((T_(2))/(T_(1)))=sqrt((480)/(120))=2`
`v_(rms_(2))=2(v_(rms))`
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