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Three moles of oxygen ar mixed with two ...

Three moles of oxygen ar mixed with two moles of helium. What will be the ratio of specific heats at constant pressure and constant volume for the mixture ?

A

`2.5`

B

`3.5`

C

`1.5`

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
For a monatomic gas like helium `gamma_(He)=5/3`
For a diatomic gas like oxygen `gamma_(O_(2))=7/5`
`therefore gamma_(mix)=(3xxgamma_(O_(2))+2xxgamma_(He))/((3+2))`
`=(3xx7/5+2xx5/3)/(5)=(21/5+10/3)/(5)=(113)/(15xx5)=1.5`
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