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(1//2) mole of helium is contained in a ...

`(1//2)` mole of helium is contained in a container at STP how much heat energy is needed to double the pressure of the gas, keeping the volume constant? Heat capacity of gas is `3 J g^(-1)K^(-1)`.

A

1436 J

B

736 J

C

1638 J

D

5698 J

Text Solution

Verified by Experts

The correct Answer is:
C

Here, `n=1/2'c_(v)=2J g^(-1)K^(-1),M=4gmol^(-1)`
`thereforeC_(V)=Mc_(V)=4xx3=12Jmol^(-1)K^(-1)`
At constant volume `P prop T.`
`therefore(P_(2))/(P_(1))=(T_(2))/(T_(1))=2,T_(2)=2T_(1)`
Rise in temperature `DeltaT=T_(2)-T_(1)=2T_(1)-T_(1)=T_(1)=273K`
Heat required, `DeltaQ=nC_(V)DeltaT=1/2xx12xx273=1638 J`
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