A hospital uses an ultrasonic scanner to locate tumours in a tissue. The operating frequency of the scanner is 3.2 MHz. The speed of sound in a tissue is 1.6 km `s^(-1)`. The wavelength of sound in the tissue is

Options

A. 0.25 mm
B. 0.5 mm
C. 0.75 mm
D. 1 mm

Answer

B

Explanation

Here, `upsilon=3.2MHz=3.2xx10^(6)Hz=3.2xx10^(6)s^(-1)`
`v=1.6 kms^(-1)=1.6xx10^(3)ms^(-1)`
Wavelength,
`lamda=v/upsilon=(1.6xx10^(3)ms^(-1))/(3.2xx10^(6)s^(-1))=0.5xx10^(-3)m=0.5mm`