A block released from rest from the top of a smooth inclined plane of angle `theta_1` reaches the bottom in time `t_1`. The same block released from rest from the top of another smooth inclined plane of angle `theta_2` reaches the bottom in time `t_2` If the two inclined planes have the same height, the relation between `t_1 and t_2` is

Options

A. `t_2/t_1=((sin theta_1)/(sin theta_2))^(1//2)`
B. `t_2/t_1=1`
C. `t_2/t_1=(sin theta_1)/(sin theta_2)`
D. `t_2/t_1 =(sin^2 theta_1)/(sin^2 theta_2)`

Answer

C