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A liquid of density rho0 is filled in a ...

A liquid of density `rho_0` is filled in a wide tank to a height h. A solid rod of length L, cross-section A and density `rho` is suspended freely in the tank. The lower end of the rod touches the base of the tank and h=L/n (where n gt 1). Then the angle of inclination `theta` of the rod with the horizontal in equilibrium position is

A

`sin^(-1)(sqrt((rho_0)/rho))`

B

`sin^(-1)(n sqrt((rho_0)/rho))`

C

`sin^(-1)(1/n sqrt((rho_0)/rho))`

D

`sin^(-1)(1/n sqrt((rho)/rho_0))`

Text Solution

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The correct Answer is:
C
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