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A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A

`1/(2pisqrt(3))`

B

`2pisqrt3`

C

`(2pi)/(sqrt3)`

D

`sqrt3/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
C
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