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A Carnot refrigerator extracts heat from...

A Carnot refrigerator extracts heat from water at `0^@C` and rejects it to room at `24.4^@C`. The work required by the refrigerator for every 1 kg of water converted into ice is
(Latent heat of ice=`336 kJ kg^(-1)`)

A

24.4kJ

B

30 kJ

C

336 kJ

D

11.2 kJ

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The correct Answer is:
B
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A Carnot refrigerator absorbs heat from water at O °C and gives it to a room at 27 °C. When it converts 2 kg of water at 0°C into ice. at 0°C, the work.done is (Latent heat of fusion of ice= 333 x 10^3Jkg^(-1) )

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Refrigerator is an apparatus which takes heat from a cold body, work is done on it and the work done together with the heat absorbed is rejected to the source. An ideal refrigerator can be regarded as Carnot's ideal heat engine working in the reverse direction. The coefficient of performance of refrigerator is defined as beta = ("Heat extracted from cold reservoir")/("work done on working substance") = (Q_(2))/(W) = (Q_(2))/(Q_(1)- Q_(2)) = (T_(2))/(T_(1) - T_(2)) A Carnot's refrigerator takes heat from water at 0^(@)C and discards it to a room temperature at 27^(@)C . 1 Kg of water at 0^(@)C is to be changed into ice at 0^(@)C. (L_(ice) = 80"kcal//kg") What is the work done by the refrigerator in this process ( 1 "cal" = 4.2 "joule" )

Refrigerator is an apparatus which takes heat from a cold body, work is done on it and the work done together with the heat absorbed is rejected to the source. An ideal refrigerator can be regarded as Carnot's ideal heat engine working in the reverse direction. The coefficient of performance of refrigerator is defined as beta = ("Heat extracted from cold reservoir")/("work done on working substance") = (Q_(2))/(W) = (Q_(2))/(Q_(1)- Q_(2)) = (T_(2))/(T_(1) - T_(2)) A Carnot's refrigerator takes heat from water at 0^(@)C and discards it to a room temperature at 27^(@)C . 1 Kg of water at 0^(@)C is to be changed into ice at 0^(@)C. (L_(ice) = 80"kcal//kg") How many calories of heat are discarded to the room?

A refrigerator converts 1.3 kg of water at 20^(@)C into ice at -15^(@)C in 1 hour. Calculate the effective power of the refrigerator. Specific latent heat of fusion of ice = 3.4 xx 10^(5) J kg^(-1) Specific heat capacity of water = 4.2 xx 10^(3) J kg^(-1) K^(-1) Specific heat capacity of ice = 2.1 xx 10^(3) J kg^(-1) K^(-1)

One kilogram of ice at 0^(@)C is mixed with one kilogram of water at 80^(@)C . The final temperature of the mixture is (Take : specific heat of water =4200 J kg^(-1) K^(-1) , latent heat of ice = 336 kJ//kg^(-1) )

A refrigerator is driven by 1000 W electric motor having an efficiency of 60% . The refrigerator is considerd as a reversible heat engine operating between 273K and 303K . Calculate the time required by it to freeze 32.5 kg of water at 0^(@)C . Heat losses may be rejected. Latent heat of fusion of ice = 336xx10^(3)J kg^(-1) .

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