Home
Class 11
PHYSICS
Calculate the stress developed inside a ...

Calculate the stress developed inside a tooth cavity filled with copper when hot tea at temperature of `57^(@)C` is drunk. You can take body (tooth) temperature to be `37^(@)C` and `alpha_(Cu) = 1.7 xx 10^(-5)//^(@)C` bulk modulus for copper `B_(Cu) = 140 xx 10^(9) N//m^(2)`.

A

`1.43 xx 10^(8) Nm^(-2)`

B

`4.13 xx 10^(8) Nm^(-2)`

C

`2.12 xx 10^(4) Nm^(-2)`

D

`3.12 xx 10^(4) Nm^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Volumetric strain in tooth cavity `= (V)/(V)`
Let `gamma` be the coefficient of volume expansion with change in temperature `DeltaT .^(@)C`.
Change in volume is
`DeltaV = gammaVDeltaT` or `(DeltaV)/(V) = gammaDeltaT`
Thermal stress in tooth cavity
`= beta xx "volumetric strain" = beta xx gamma DeltaT`
`= beta xx 3alpha DeltaT`
`= 140 xx 10^(9) xx 3 xx 1.7 xx 10^(-5) xx (57^(@)C - 37^(@)C)`
` = 1.43 xx 10^(8) N m^(-2)`.
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS|Exercise Specific Heat Capacity|5 Videos
  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS|Exercise Calorimetry|4 Videos
  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS|Exercise Measurement Of Temperature|2 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTIONS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos
  • THERMODYNAMICS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

What is the thermal stress developed inside a tooth cavity filled with copper when hot tea at temperature of 57^(@)C is drunk? You can take body (tooth) temperature to be 37^(@)C and alpha_(Cu) = 1.7 xx 10^(-5)//^(@)C and bulk modulus for copper = 14 xx 10^(10) N//m^(2) .

A surveryor uses a steel measuring tape that is exactly 50.000 m long at a temperature of 20^(@)C What is its length on a hot summer day when the temperature is 35^(@)C ? (alpha_("stell")=1.2xx10^(-5)K^(-1))

An iron sphere has a radius of 10 cm at a temperature of 0^(@)C . Calculate the change in volume of the sphere if it is heated to 100^(@)C . Given alpha_(Fe) = 1.1 xx 10^(-6).^(@)C^(-1)

A wire of cross sectional area 3 mm^(2) is just stretched between two fixed points at a temperature of 20^(@)C . Then the tension in the wire when the temperature falls to 10^(@)C is, (alpha =1.2 xx 10^(-5) //""^(@)C, Y=2xx10^(11) N//m^(2))

What is the percentage change in length of 1m iron rod it its temperature changes by 100^(@)C. alpha for iron is 2 xx 10^(-5)//"^(@)C .

A steel wire 2mm in diameteris ust streched between two dixed point at a temperature of 20^(@)C . Determine its tension when its temperature falls to 10^(@)C . Linear expansivity of steel =11 xx 10^(-6)//K, Young modulus =2 xx 10^(11)//m^(-2)

What should be the length of steel and copper rods at 0^(@)C that the length of steel rod is 5 cm longer than copper at all termperature? Given alpha_(Cu) = 1.7 xx 10^(5) .^(@)C^(-1) and alpha_(steel) = 1.1 xx 10^(5) .^(@)C^(-1) .

Two rods of equal cross sections, one of copper and the other of steel, are joined to form a composite rod of length 2.0 m at 20^@C , the length of the copper rod is 0.5 m. When the temperature is raised to 120^@C , the length of composite rod increases to 2.002m. If the composite rod is fixed between two rigid walls and thus not allowed to expand, it is found that the lengths of the component rods also do not change with increase in temperature. Calculate Young's moulus of steel. (The coefficient of linear expansion of copper, alpha_c=1.6xx10^(-5@)C and Young's modulus of copper is 1.3xx10^(13)N//m^(2) ).