Home
Class 11
PHYSICS
When 1.5 kg of ice at 0^(@)C mixed wi...

When `1.5 kg` of ice at `0^(@)C` mixed with `2` kg of water at `70^(@)C` in a container, the resulting temperature is `5^(@)C` the heat of fusion of ice is (`s_("water") = 4186 j kg^(-1)K^(-1))`

A

`1.42 xx 10^(5) j kg^(-1)`

B

`2.42 xx 10^(5) j kg^(-1)`

C

`3.42 xx 10^(5) j kg^(-1)`

D

`4.42 xx 10^(5) j kg^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Heat lost by water `= m_(w)s_(w) (T_(i) - T_(f))`
`= 2 xx 4186 xx (70-5) = 544180 j`
Heat required to rise temperature of melt ice `= m_(i)L_(f) = 1.5 xx L_(f)`
Heat required to rise temperature of ice
`= m_(i)s_(w) (T_(f) - T_(0)) = 1.5 (4186) xx (5-0^(@)) = 31395 j`
By the principle of calorimetry
Heat lost = heat gained
`544180 = 1.5 L_(f) + 31395`
`:. L_(f) = (512785)/(1.5) = 341856.67 = 3.42 xx 10^(5) j kg^(-1)`
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS|Exercise Change Of State|13 Videos

  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS|Exercise Heat Transfer|26 Videos

  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS|Exercise Specific Heat Capacity|5 Videos

  • SYSTEM OF PARTICLES AND ROTATIONAL MOTIONS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • THERMODYNAMICS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

When 0.15 kg of ice at 0^(@)C is mixed with 0.30 kg of water at 50^(@)C in a container, the resulting temperature is 6.7^(@)C . Calculate the heat of fusion of ice. (s_(water) = 4186 J kg^(-1)K^(-1))

When a 0.45 kg of ice at 0^(@)C mixed with 0.9 kg of water at 55^(@)C in a container, the resulting temperature is 10^(@)C . Calculate the heat of fusion of ice. Specific heat of water is 4186 j kg^(-1) K^(-1) .

On mixing 0.35 kg of ice at 0^@C with 0.8 kg of water at 45^@C in a container, the final temperature becomes 20^@C . What will be the heat of fusion of ice? (Specific heat of water = 4186 J kg^(-1) K^(-1) )

100 g of ice at 0^(@)C is mixed with 0.25 kg of water at 0^(@)C The net transfer of heat is _______

2 kg ice at 0^@C is mixed with 8 kg of water at 20^@C . The final temperature is

One kg of ice at 0^(@)C is mixed with 1 kg of water at 10^(@)C . The resulting temperature will be