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If a ball of 80 kg mass hits an ice cube...

If a ball of `80` kg mass hits an ice cube and temperature of ball is `100 .^(@)C`, then how much ice converted into water ? (Specific heat of ball is `0.2 cal g^(-1)`, Latent heat of ice `= 80 cal g^(-1)`)

A

20 g

B

`200 g`

C

`2 xx 10^(3) kg`

D

`2 xx 10^(4)g`

Text Solution

Verified by Experts

The correct Answer is:
D
If m is the mass of ice metled, then heat spent in melting = heat supplied by the ball
`mL = sMDeltaT`
`m xx80 = 0.2 xx (80 xx 1000) xx 100`
or `m = 2 xx 10^(4) g`
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