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If f(x) = 2 x t 0 e (t 2)(t 3)dt for all...

If f(x) = 2 x t 0 e (t 2)(t 3)dt for all x (0, ), then (A) f has a local maximum at x = 2 (B) f is decreasing on (2, 3) (C) there exists some c (0, ) such that f (c) = 0

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Let f(x)={|x|,f or 0<|x|<=2:1, for x=0 Then at x=0,f has (a)a local maximum (b) no local maximum (c)a local minimum (d) no extremum

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