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A resistor is marked with the rings colo...

A resistor is marked with the rings coloured brown, balck, green, and gold. The resitance in ohm is

A

`(3.5xx10^(5)pm5%)`

B

`(1.10xx10^(5)pm10%)`

C

`(8xx10^(6)pm5%)`

D

`(1xx10^(6)pm5%)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the resistance of a resistor marked with the color bands brown, black, green, and gold, we can follow these steps: ### Step 1: Identify the Color Codes The first step is to identify the values associated with each color band according to the standard resistor color code: - **Brown**: 1 - **Black**: 0 - **Green**: 10^5 (or 100000) - **Gold**: Tolerance of ±5% ### Step 2: Determine the Digits The first two colors represent the significant digits of the resistance value: - The first digit (brown) is **1**. - The second digit (black) is **0**. ### Step 3: Form the Base Value Combine the first two digits to form the base value: - Base value = 10 (from combining 1 and 0). ### Step 4: Apply the Multiplier The third color (green) indicates the multiplier: - The multiplier is **10^5**. ### Step 5: Calculate the Resistance Now, we calculate the resistance using the base value and the multiplier: - Resistance = Base value × Multiplier - Resistance = 10 × 10^5 = 10^6 ohms. ### Step 6: Determine the Tolerance The last color (gold) indicates the tolerance: - Tolerance = ±5%. ### Final Answer Thus, the resistance of the resistor is: - **1,000,000 ohms (or 1 MΩ) ± 5%**. ### Summary The resistance in ohms is **1 MΩ ± 5%**. ---
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