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A battery having 12V emf and internal re...

A battery having 12V emf and internal resistance `3Omega` is connected to a resistor. If the current in the circuit is 1A, then the resistance of resistor and lost voltage of the battery when circuit is closed will be

A

`7Omega,7V`

B

`8Omega,8V`

C

`9Omega,9V`

D

`9Omega,10V`

Text Solution

Verified by Experts

The correct Answer is:
C
Here, `epsi=12V, r=3Omega, I=1A,V=IR=epsi-Ir`
`therefore R=(epsi-Ir)/(I)=(12-1xx3)/(1)=12-3=9Omega`
and `V=IR=1xx9=9V`
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