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Four resistances of 3Omega, 3Omega, 3Ome...

Four resistances of `3Omega, 3Omega, 3Omega and 4Omega` respectively are used to form a Wheatstone bridge. The `4Omega` resistance is short circuited with a resistance R in order to get bridge balanced. The value of R will be

A

`10Omega`

B

`11Omega`

C

`12Omega`

D

`13Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
The bridge will be balanced when the shunted resistance is of the value of `3Omega`
`therefore 3=(4xxR)/(4+R) ,12+3=4R, therefore R=12Omega`
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