Home
Class 12
PHYSICS
In the shown figure, bridge is balanced,...

In the shown figure, bridge is balanced, the current flowing through `2Omega` resistance is

A

`(10)/(7)A`

B

`(11)/(7)A`

C

`(13)/(7)A`

D

`(8)/(7)A`

Text Solution

Verified by Experts

The correct Answer is:
A
Let I be the current flowing through PQR then the current flowing through PSR is (2-I) A. Now since galvanometer no deflection then the volatage through arm PQR is sam as the voltage through arm PSR.
`I(4+2)=(2-I)(10+5),6I=30-15I`
`21I=30 Rightarrow I=(30)/(21)=(10)/(7)A`
Hence, the current through `2 Omega` resistor is `(10)/(7)A`
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NCERT FINGERTIPS|Exercise Meter Bridge|4 Videos

  • CURRENT ELECTRICITY

    NCERT FINGERTIPS|Exercise Potentiometer|7 Videos

  • CURRENT ELECTRICITY

    NCERT FINGERTIPS|Exercise Kirchoff'S Law|11 Videos

  • COMMUNITCATION SYSTEMS

    NCERT FINGERTIPS|Exercise HOTS|10 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

In the circuit, the current flowing through 10Omega resistance is

In the circuit, the current flowing through 10 Omega resistance

The current flowing in 3Omega Resistance will be

In the following network, the current flowing through 15 Omega resistance is

Calculate the current flows through resistance 2Omega .

In the circuit in figure, the current flowing 5 Omega resistance is :

In the figure shown the current flowing through 2R is:

Using Kirchoff's rules determine the value of unknown resistance R in the circuit shown in figure, so that no current flows through 4 Omega resistance. Also find the potential difference between A and D.