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In the circuit P != R, the reading of t...

In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then

A

`I_(R)=I_(G)`

B

`I_(P)=I_(G)`

C

`I_(Q)=I_(G)`

D

`I_(Q)=I_(R)`

Text Solution

Verified by Experts

The correct Answer is:
A
This method is kelvin's method of determining resistance of galvanometer by Wheatstone bridge circuit. Deflection in galvanometer G is same with switch S open or closed. It means that there is no current through S. This happens when the potentials at the two ends of S are same. This is the condition of balanced Wheatstone bridge.
`therefore I_(p)=I_(Q)and I_(R) =I_(G)`
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Knowledge Check

  • In the circuit shown, PneR and the reading of the galvanometer is same with switch S open or closed. Then

    A
    `I_(R )= l_(G)`
    B
    `I_(p)=l_(G)`
    C
    `l_(Q) = l_(G)`
    D
    `I_(R)=I_(Q)`

  • In the circuit shown P ne R the reading of galvonometer is same switch S open or closed. Then

    A
    `I_(R)=I_(G)`
    B
    `I_(P)=I_(G)`
    C
    `I_(Q)=I_(G)`
    D
    `I_(Q)=I_(S)`

  • In the circuit shown as P != R and the reading of the galvanometer G is same with the switch open or closer. Then

    A
    `I_R = I_G`
    B
    `I_P = I_G`
    C
    `I_Q = I_G`
    D
    `I_Q = I_R`