Calculate the steady state current in the 2- ohm resistor shown in the circuit in the figure. The intermal resistance of the battery is negligible and the capacitance of the condenser C is 0.2 microfarad.

Options

A. 0.6A
B. 0.9A
C. 1.2A
D. 0.1A

Answer

B

Explanation

At steady state, no current flows throght the capacitor branch of the circuit `2Omega and 3Omega` are in paralle. Let their combined resistance be R.
`therefore R=(2xx3)/(2+3)=(2xx3)/(5)=1.2Omega`
Net current supplied=`(6)/(1.2+2.8)`
I=5A
I divides into `I_(1) and I_(2)`
`2I_(1)=3I_(2) ("Potential Difference is same"]`
`or I_(2)=2I_(2)//3`
`I_(1)+I_(2)=1.5 or I_(1)=(2I_(1))/(3)=1.5`
`or (5I_(1))/(3)=1.5 or I_(1)=(1.5xx3)/(5)A=0.9A`