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The output of a step-down transformer is...

The output of a step-down transformer is measured to be `24 V` when connected to a 12 watt light bulb. The value of the peak current is

A

`(1)/(sqrt(2))A`

B

`sqrt(2)A`

C

`2A`

D

`2sqrt(2)A`

Text Solution

Verified by Experts

The correct Answer is:
A
Here, `V_(s)=24 V, P_(s) =12 W`
`I_(s)=(P_(s))/(V_(s))=(12)/(24)=0.5 A , I_(m)=sqrt(2) I_(s)=sqrt(2)xx0.5=(1)/(sqrt(2)) A`
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