In Young's double slit experiment, the `10^(th)` maximum of wavelength `lambda_(1)` is at a distance `y_(1)` from its central maximum and the `5^(th)` maximum of wavelength `lambda_(2)` is at a distance `y_(2)` from its central maximum. The ratio `y_(1)//y_(2)` will be

Options

A. `(2lambda_(1))/(lambda_(2))`
B. `(2lambda_(2))/(lambda_(1))`
C. `(lambda_(1))/(2lambda_(2))`
D. `(lambda_(2))/(2lambda_(1))`

Answer

A

Explanation

We know that position of `m^(th)` bright fringe is `y_(m)=(m lambda D)/(d).`
Therefore, for wavelength `lambda_(1),y_(1)=(10lambda_(1) D)/(d)`
and for wavelength `lambda_(2),y_(2)=(5lambda_(2) D)/(d), :. (y_(1))/(y_(2))=(2lambda_(1))/(lambda_(2)).`