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In a double slit experiment, the distanc...

In a double slit experiment, the distance between slits in increased ten times whereas their distance from screen is halved then the fringe width is

A

becomes `(1)/(20)`

B

becomes `(1)/(90)`

C

it remains same

D

becomes `(1)/(10)`

Text Solution

Verified by Experts

The correct Answer is:
A

Fringe width, `beta=(D lambda)/(d) " "` … (i)
According to the question, `D'=(D)/(2)` and `d'=10d`
` :. beta'=(D'lambda)/(d')=((D//2)lambda)/(10d)=(1)/(20)=(D lambda)/(d)`
` implies beta'=(beta)/(20) " " ` (Using (i))
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