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In double slit experiment using light of...

In double slit experiment using light of wavelength `600 nm`, the angular width of a fringe formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?

A

`3.44xx10^(-4)m`

B

`1.54xx10^(-4)m`

C

`1.54xx10^(-3)m`

D

`1.44xx10^(-3)m`

Text Solution

Verified by Experts

The correct Answer is:
A
Angular width fo fringe,
`theta=0.1^(@)=0.1xx(pi)/(180)"rad" =(3.14)/(1800)"rad" `
` :. d=(lambda)/(theta)=(600xx10^(-9))/(3.14//1800)=3.44xx10^(-4) m`
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