In a Young's double slit experiment, the angular width of a fringe formed on a distant screen is `1^(@)` . The slit separation is 0.01 mm. The wavelength of the light is

Options

A. 0.174 nm
B. 0.174 Ã…
C. 0.174 `mu m`
D. `0.174 xx 10^(-4)m`

Answer

C

Explanation

Angular fringe width, `theta = (lambda)/(d)`
` :. Lambda= theta d`
Here, `d=0.01 mm=10^(-5)m, theta=1^(@)=(pi)/(180)`radians
`lambda=(pi)/(180)x10^(-5)=1.74xx10^(-7)m`
` " " =0.174 xx10^(-6)m=0.174 mu m`