In Young's double slit experiment, the distance d between the slits `S_(1)` and `S_(2)` is 1 mm. What should the width of each slit be so as to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern ?

Options

A. 0.9 mm
B. 0.8 mm
C. 0.2 mm
D. 0.6 mm

Answer

C

Explanation

The angular separation between n bright
fringes, ` theta_(n)=(x_(n))/(D)=(n lambda)/(d) " " ( :' x_(n)=(n lambda D)/(d))`
For 10 bright fringes, `theta_(10)=(10 lambda)/(d)`
The angular width of the central maximum in the diffraction pattern due to slit of width a is
`2theta_(1)=(2 lambda)/(a)`
Now`(10lambda)/(d)le (2lambda)/(a) " or " a le(d)/(5)=(1)/(5)mm=0.2mm`