A telescope is used to resolve two stars separated by `4.6xx10^(-6)` rad. If the wavelength of light used is `5460 Å` , what should be the aperture of the objective of the telescope ?

Options

A. 0.1488 m
B. 0.567 m
C. 1 m
D. 2 m

Answer

A

Explanation

Aperture of the telescope, `D=(1.22lambda)/(d theta)`
Here, `lambda=5460Ã…=5460xx10^(-10)m, d theta=4.6xx10^(-6)`rad,
` :. D=(1.22 xx 5460xx10^(-10))/(4.6xx10^(-6))=0.1488` m