The critical angle of a certain medium is `sin ^(-1)((3)/(5))`. The polarizing angle of the medium is :

Options

A. ` "sin"^(-1)((4)/(5))`
B. ` "tan"^(-1)((5)/(3))`
C. ` "tan"^(-1)((3)/(4))`
D. ` "tan"^(-1)((4)/(3))`

Answer

B

Explanation

Here, critical angle, `i_(c)="sin"^(-1)((3)/(5))`
` :. "sin"i_(c)=(3)/(5)`
As `mu=(1)/("sin"i_(c))=(5)/(3)`
According to Brewster's law
` "tan"i_(p)=mu`
where `i_(p)` is the polarising angle
` :. "tan"i_(p)=(5)/(3)impliesi_(p)="tan"^(-1)((5)/(3))`