Light is incident on a glass surface at polarizing angle of `57.5^(@)` Then the angle between the incident ray and the refracted ray is

Options

A. `57.5^(@)`
B. `115^(@)`
C. `205^(@)`
D. `145^(@)`

Answer

C

Explanation

When a light is incident at polarising angle, the reflected and refracted rays are perpendicular to each other as shown in the figure. where `i_(p)` is the angle of incidence and r is the angle of reflection, r' is the angle of refraction. Given, `i_(p)=57.5^(@)`
Let `theta` be the angle between the incident ray and the refracted ray.
From figure,
`theta=i_(p)+r+90^(@)=2i_(p)+90^(@)`
` " " = 2 xx 57.5^(@)+90^(@)=205^(@) " " [ :' i_(p)=r]`