Home
Class 12
PHYSICS
The time taken by a photoelectron to com...

The time taken by a photoelectron to come out after the photon strikes is approximately

A

`10^(-1)s`

B

`10^(-4)s`

C

`10^(-10)s`

D

`10^(-16)s`

Text Solution

Verified by Experts

The correct Answer is:
C

(c ) : Emission of photoelectron starts from the surface after incidence of photons in about `10^(-10)` s.
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS|Exercise Einstein'S Photoelectric Equation : Energy Quantum Of Radiation|23 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS|Exercise Particle Nature Of Light : The Photon|19 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS|Exercise Photoelectric Effect|2 Videos
  • CURRENT ELECTRICITY

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos
  • ELECTRIC CHARGES AND FIELDS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

The pH of tears coming out of a person's eye is approximately

The time taken for 90% of a first order reaction to be completed is approximately

The ratio of number of photoelectrons ejected to the number of the photons falling on a metal surface is..........than.......... .

Ground state energy of H-atom is (-E_(1)) ,t he velocity of photoelectrons emitted when photon of energy E_(2) strikes stationary Li^(2+) ion in ground state will be:

A uniform electric field of magnitude E exists in between two parallel metal plates , as shown in the figure given below. One particle of mass m and charge q is projected along the central line between the plates. Particle just missed to strike upper plate , while coming out of plates. Find : (a)Time taken by the particle to come out of plates. (b)Speed of the particle as it comes out of plates. (c) Angle of deviation suffered by particle. The length of the plates is L and the distance between the plates is d. Ignore gravity .

A particle startsits SHM at t=0 . At a particular instant on its way to extreme position , x= (A)/(2) . Find the time taken by the particle to come back to this point after passing through the extreme position. Hint : t_(1) = time taken to go from x=0 to x= (A)/(2) t_(2) = time taken to go to extreme position and come back to mean position = (T)/(2) Required time = (T)/(2) - t_(1)

The time required in emitting photoelectrons is