In a photoelectric experiment, if both the intensity and frequency of the incident light are doubled, then the saturation photoelectric current

Options

A. remains constant
B. is halved
C. is doubled
D. becomes four times

Explanation

To solve the problem, we need to understand how the saturation photoelectric current is affected by changes in the intensity and frequency of the incident light in a photoelectric experiment.

### Step-by-Step Solution:

1. **Understanding Saturation Photoelectric Current**:
- The saturation photoelectric current is the maximum current that can be achieved in a photoelectric experiment when all emitted photoelectrons are collected by the anode.
- This current is directly proportional to the intensity of the incident light.

2. **Effect of Intensity**:
- The intensity of light is defined as the power per unit area. When the intensity of the incident light is doubled, it means that more photons are striking the surface per unit time.
- Since the saturation current is directly proportional to the intensity, if the intensity is doubled, the saturation photoelectric current will also double.

3. **Effect of Frequency**:
- The frequency of the incident light affects the energy of the photons (given by the equation \(E = hf\), where \(h\) is Planck's constant and \(f\) is the frequency).
- However, the saturation photoelectric current is independent of the frequency of the incident light. This means that even if the frequency is increased, it does not affect the saturation current.

4. **Combining Effects**:
- In this scenario, both the intensity and frequency of the incident light are doubled.
- Since the saturation current depends only on the intensity, and we have established that doubling the intensity results in doubling the saturation current, we conclude that the saturation current will double.

5. **Final Conclusion**:
- Therefore, if both the intensity and frequency of the incident light are doubled, the saturation photoelectric current will also double.

### Answer:
The saturation photoelectric current will double.