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The photoelectric cut off voltage in a c...

The photoelectric cut off voltage in a certain experiment is 1.5V. What is the maximum kinetic energy of photoelectrons emitted? `e=1.6xx10^(-19)C`.

A

2.4 eV

B

1.5 eV

C

3.1 eV

D

4.5 eV

Text Solution

Verified by Experts

The correct Answer is:
B
(b) : Here, `V_(0)=1.5V`,
Maximum kinetic energy `=eV_(0)=1.5eV`
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