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There are two sources of light, each emitting with a power of `100W`. One emits X-rays of wavelength `1nm` and the other visible light at `500nm`. Find the ratio of number of photons of X-rays to the photons of visible light of the given wavelength?

A

`1:500`

B

`1:400`

C

`1:300`

D

`1:200`

Text Solution

Verified by Experts

The correct Answer is:
A

(a) : `"Here",P=100W,lamda_(1)=1nm,lamda_(2)=500nm`
`"Let"n_(1) and n_(2)"be the number of photons of X-rays and visible light emitted from the two two sources"`
`:.n_(1)(hc)/(lamda_(1))=n_(2)(hc)/(lamda_(2)) or (n_(1))/(lamda_(1))=(n_(2))/(lamda_(2)) or (n_(1))/(n_(2))=(lamda_(1))/(lamda_(2))=(1)/(500)`
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