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Which of these particles having the same...

Which of these particles having the same kinetic energy has the largest de Broglie wavelength ?

A

Electron

B

Alpha particle

C

Proton

D

Neutron

Text Solution

Verified by Experts

The correct Answer is:
A

(a) : `As" "lamda=(h)/(sqrt(2mK))" "so" "lamdaprop(1)/(sqrt(m))`
Out of the given particles m is least for electron, therefore electron has the largest value of de Broglie wavelength.
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