Assuming an electron is confined to a 1 nm wide region. Find the uncertainty in momentum using Heisenberg uncertainty principle.
`("Take h"=6.63xx10^(-34)Js)`

Options

A. `1.05xx10^(-25)"kg m s"^(-1)`
B. `2.03xx10^(-31)"kg m s"^(-1)`
C. `3.05xx10^(-34)"kg m s"^(-1)`
D. `3.05xx10^(-32)"kg m s"^(-1)`

Answer

A

Explanation

(a) : Here `Deltax=1nm=10^(-9)m`
By Heisenberg uncertainty principle, `DeltaxDeltap=h`
`:.Deltap=(h)/(Deltax)=(h)/(2piDeltax)" "( :.h=(h)/(2pi))`
`=(6.63xx10^(-34))/(2xxpixx10^(-9))=0.05xx10^(-25)kg" m s"^(-1)`