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A parallel beam of monochromatic radiati...

A parallel beam of monochromatic radiation of cross-section area `A(lt pi a^(2))`, intensity `I` and frequency `v` is incident on a solid conducting sphere of work function`phi_(0)[hv gt phi_(0)]` and radius `'a'`. The sphere is grounded by a conducting wire. Assume that for each incident photon one photoelectron is ejected. Just after this radiation is incident on initially unchanged sphere, the current through the conducting wire is:

A

`(IAe)/(hv)`

B

`(IAe)/(2hv)`

C

`(2IAe)/(hv)`

D

`(2)/(3)(IAe)/(hv)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) : Energy of each incident photon = hv.
Total energy incident per second on sphere = IA
`:."No. of photons incident on sphere per second"=(IA)/(hv)`
`:."No. of photoelectrons ejected per second"=(IA)/(hv)`
Current through the conducting wire = charge flowing per second through wire = `(IAe)/(hv)`
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