Home
Class 12
PHYSICS
An electron is moving with an initial ve...

An electron is moving with an initial velocity `vecv=v_(0)hati` and is in a magnetic field `vecB=B_(0)hatj`. Then it's de-Broglie wavelength

A

remains constant

B

increases with time

C

decreases with time

D

increases and decreases periodically

Text Solution

Verified by Experts

The correct Answer is:
A

(a) : Here, `vec(v)=v_(0)hat(i),vec(B)=B_(0)hat(j)`
As this force is perpendicular to `vec(v)andvec(B)`, so the magnitude of `vec(v)` will not change. i.e., momentum (=mv) will remain constant in magnitude.
Therefore, de Broglie wavelength , `lamda(=(h)/(mv))` remeins constant.
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS|Exercise Higher Order Thinking Skills|8 Videos
  • CURRENT ELECTRICITY

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos
  • ELECTRIC CHARGES AND FIELDS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

An electron (mass m) with an initial velocity vecv=v_(0)hati is in an electric field vecE=E_(0)hatj . If lambda_(0)h//mv_(0) . It's de-broglie wavelength at time t is given by

A proton is fired from origin with velocity vecv=v_0hatj+v_0hatk in a uniform magnetic field vecB=B_0hatj .

An electron of mass 'm' is moving with initial velocity v_0hati in an electric field vecE=E_0hati Which of the following is correct de Broglie wavelength at a given time t (lamda_0 is initial de Broglie wavelength ).

An electron (mass m) with initial velocity vecv = v_0 hati + 2v_0 hatj is in an electric field vecE = E_0 hatk . If lamda_0 is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by :

An electron (mass m) with an initial velocity v=v_(0)hat(i)(v_(0)gt0) is in an electric field E=-E_(0)hat(l)(E_(0)="constant"gt0) . Its de-Broglie wavelength at time t is given by

An electron in an electron microscope with initial velocity v_(0)hati enters a region of a stray transverse electric field E_(0)hatj . The time taken for the change in its de-Broglie wavelength from the initial value of lambda to lambda//3 is proportional to

An electron (mass m ) with initival velocity vecv = v_(0) hati + v_(0) hatj is the an electric field vecE = - E_(0)hatk . It lambda_(0) is initial de - Broglie wavelength of electron, its de-Broglie wave length at time t is given by :

An electron moving with velocity vecv_(1)=1hati m//s at a point in a magnetic field experiences a force vecF_(1)=-ehatjN where e is the charge of electron.If the electron is moving with a velocity vecv_(2)=hati-hatj m//s at the same point, it experiences a force vecF_(2)=-e(hati+hatj)N . Find the magnetic field and the force the electron would experience if it were moving with a velocity vecv_(3)=vecv_(1)xxvecv_(2) at the same point.