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0.92 gm of an organic compound containin...

0.92 gm of an organic compound containing carbon, hydrogen, and oxygen was analysed by combustion method. The increase in the mass of the U-tube and the potash bulbs at the end of the operation was found to the 1.08 gm and 1.76 gm respectivley. Determine the percentage composition of the compound.

Text Solution

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Increase in mass of U-tube `= 1.08g`
Mass of water formed `= 1.08g`
Since, 18g of water contain hydrogen `= 2g`
`1.08g` of water contain hydrogen `=(2)/(18) xx 1.08g`
Mass of compound taken for analysis `= 0.92g`
Percentage of hydrogen `=(2)/(18) xx (1.08)/(0.92) xx 100 = 13.04` ltbr. Increase in mass of potash bulbs `= 1.76 g`
Mass of carbon dioxide formed `=1.76g`
Since, 44g of carbon dioxide contain carbon `= 12g`
`1.76g` of carbon dioxide contain carbon `= (12)/(44) xx 1.76g`
Percentage of carbon `= (12)/(44) xx (1.76)/(0.92) xx 100 = 52.17`
Percentage of oxygen `= 100-` (per cent of `C+` per cent of H)
`= 100 -(52.17 +13.04)`
`= 100 - 65.21 = 34.79`
Composition of the compound `: C = 52.17%, H = 13.04% O = 34.79%`
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