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0.38 gm of a silver salt of a dibasic ac...

0.38 gm of a silver salt of a dibasic acid on igition gave 0.27 gm of silver. Calculate the molecular mass of the acid.

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Mass of silver salt `= 0.38g`
Mass of silver `= 0.27g`
`("Eq. mass of silver salt")/("Eq. mass of silver") = ("Mass of silver salt")/("Mass of silver")`
Eq. mass of silver salt `= (0.38)/(0.27) xx 108`
or `E +107 = (0.38)/(0.27) xx 108` (E = Eq. mass of acid)
or `E = [(0.38)/(0.27) xx 108 - 107] = 45`
Mol. mass of the acid = Eq mass `xx` Basicity `= 45 xx 2 = 90`
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