Home
Class 11
CHEMISTRY
5mL of a gas containing only carbon and ...

5mL of a gas containing only carbon and hydrogen were mixed with an excess of oxygen (30mL) and the mixture exploded by means of an electric spark. After the explosion, the volume of the mixed gases remaining was 25mL. On adding a concentrated solution of potassium hydroxide, the volume further diminished to 15mL, the residual gas being pure oxygen. All volumes have been reduced to NTP. Calculate the molecular formula of the hydrocarbon gas.

Text Solution

Verified by Experts

Let the formula of the hydrocarbon be `C_(x)H_(y)`. Its combustion can be shows by the following equation:
`{:(C_(x)H_(y)+,(x+(y)/(4))O_(2)rarr,xCO_(2)+(y)/(2)H_(2)O),(1vol,(x+(y)/(4))mL,xvol),(5mL,5(x+(y)/(4))mL,5xvol):}`
Volume of carbon dioxide produced `= (25 - 15) = 10mL`
`5x = 10`
or `x = 2`
Volume of oxygen used `= (30 - 15) = 15mL`
`5[x+(y)/(4)] = 15` or `x +(y)/(4) = (15)/(5) = 3`
or `2 +(y)/(4) = 3`
or `(y)/(4) = 3 - 2 = 1`
or `y = 4`
Thus, the molecular formula of the hydrocarbon `= C_(2)H_(4)`
Promotional Banner

Topper's Solved these Questions

  • CHARACTERISATION OF ORGANIC COMPOUNDS

    OP TANDON|Exercise ILLUSTRATIONS OF OBJECTIVE QUESTIONS|14 Videos

  • CHARACTERISATION OF ORGANIC COMPOUNDS

    OP TANDON|Exercise PROBLEMS FOR PRACTICE|2 Videos

  • ATOMIC STRUCTURE

    OP TANDON|Exercise Integer Answer Type Questions|6 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    OP TANDON|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|5 Videos

Similar Questions

Explore conceptually related problems

5 ml of a gas containing only carbon and hydrogen were mixed with an excess of oxygen (30 ml) and the mixture exploded by means of an electric spark. After the explosion, the volume of the mixed gases remaining was 25 ml. On adding a concentrated solution of potassium hydroxide, the volume further diminished to 15 ml of the residual gas being pure oxygen. All volumes have been reduced to N.T.P. Calculate the molecular formula of the hydrocarbon gas.

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compopund (F) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (B) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (C) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (D) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (E) is:

5 " mL of " a gas A containing only C and H was mixed with an excess of O_2 (30 mL) and the mixture was exploded by means of electric sperk. After explosion, the remaining volume of the mixed gases was 25 mL. On adding a concentrated solution of KOH, the volume further diminished to 15 mL. The residual gas was pure oxygen, The molecular formula of the gas A is.

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. The molecular formula of gas (A) is: