9.9g of amide with molecular formula `C_(4)H_(5)N_(x)O_(y)` on heating with alkali liberated 1.7g of ammonia. If the percentage of oxygen is 33.33% then the ratio of 'N' and 'O' atoms in the compound is:

Options

A. `1:1`
B. `1:2`
C. `2:3`
D. `3:2`

Answer

B

Explanation

Amide `C_(4)H_(5)N_(x)O_(y)` will give x mol `NH_(3)`.
`:.` Molecular mass of amide `=(9.9)/(1.7) xx 17x = 99x`
% Nitrogen in the amide `= (14x)/(99x) xx 100 = 14.14`
Ratio of number of atoms of 'N' and 'O'
`= (14.14)/(14): (33.33)/(16) = 1:2`