The shortest distance between line `y"-"x""=""1` and curve `x""=""y^2` is : (1) `(sqrt(3))/4` (2) `(3sqrt(2))/8` (3) `8/(3sqrt(2))` (4) `4/(sqrt(3))`

The shortest distance between line y-x=1 and curve is : (1)(sqrt(3))/(4) (2) (3sqrt(2))/(8) (3) (8)/(3sqrt(2))(4)(4)/(sqrt(3))

The shortest distance between the line yx=1 and the curve x=y^(2) is (A)(3sqrt(2))/(8) (B) (2sqrt(3))/(8) (C) (3sqrt(2))/(5) (D) (sqrt(3))/(4)

The shortest distance between the line x=y and the curve y^(2)=x-2 is (a) 2 (b) (7)/(8) (c) (7)/(4sqrt(2)) (d) (11)/(4sqrt(2))

The shortest distance between curves y^(2) =8x " and "y^(2)=4(x-3) is

Solve (2)/(sqrt(x))+(3)/(sqrt(y))=2 ;(4)/(sqrt(x))+(3)/(sqrt(y))=2

(2)/(sqrt(x))+(3)/(sqrt(y))=2 and (4)/(sqrt(x))-(9)/(sqrt(y))=-1

{:((2)/(sqrt(x))+ (3)/(sqrt(y)) = 2),((4)/(sqrt(x))-(9)/(sqrt(y)) = -1):}

Solve: (2)/(sqrt(x))-(3)/(sqrt(y))=2 and (4)/(sqrt(x))-(9)/(sqrt(y))=-1

The distance between the parallel lnes y=2x+4 and 6x-3y-5 is (A) 1 (B) 17/sqrt(3) (C) 7sqrt(5)/15 (D) 3sqrt(5)/15

The equaiton of the line which bisects the obtuse angle between the lines x-2y+4=0 and 4x-3y+2=0 (A) (4-sqrt(5))x-(3-2(sqrt(5)) y+ (2-4sqrt(5))=0 (B) (3-2sqrt(5)) x- (4-sqrt(5))y+ (2+4(sqrt(5))=0 (C) (4+sqrt(5)x-(3+2(sqrt(5))y+ (2+4(sqrt(5))=0 (D) none of these