In Young’s double-slit experiment, the separation between two slits is`" d = 0.32 mm "`and the wavelength of light used is` lambda = 5000overset(@)A`. Find the number of maxima in the angular range`-sin^(-1)(0.6)lethetalesin^(-1)(0.6)`

In Young's double slit experiment the distance between the two slits is d and wavelength of the light used is lambda . The angular width of the fringe

In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is 4 xx 10^(-7) m . If the width of the fringe on the screen is 4 mm , the distance between screen and slit is

In a Young’s double slit experiment, the angular width of a fringe formed on distant screen is 0.1^@ . The wave length of light used is 6000 overset@A . What is the spacing between the slits ?

In Young's double slit experiment, slit separation is 0.6 mm and the separation between slit and screen is 1.2m . The angular width is (the wavelength of light used is 4800Å )

In a Young's double slit experiment if the slit separation is twice the wavelength of light used then the maximum number of interference maxima is

In a Young's double slit experiment the separation between the slits is 0.10 mm, the wavelength of light used is 600 mm and the interference pattern is observed on a screen 1.0 m away. Find the separation between the successive bright fringes.

In Young.s double slit experiment the separation d between the slits is 2mm, the wavelength lambda of the light used is 5896 A^(0) and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0.20^(0) . To increase the fringe angular width to 0.21^(0) (with same lambda and D) the separation between the slits needs to be changed to