" 3) "y=(5x+10)/(2);4x-5=-y

Solve the simultaneous equations using Cramer's rule : y=(5x-10)/2 , 4x + y =-5

Solve the simultaneous equations using Cramer's rule : y=(5x-10)/2 , 4x + y =-5

If (3x -4y) : (2x -3y) = (5x -6y) : (4x -5y) , find : x : y .

x^(2)x2y^(3)x5x^(3)y^(2) is equal to: 10x^(2)y^(5) (b) 10x^(5)y^(2)10x^(5)y^(5)(d)x^(5)y^(5)

2-2 (3x-y) = 10 (4-y) -5x = 4 (yx)

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))

Simplify : (2x+y)^(5)-5y(2x+y)^(4)+10y^(2)(2x+y)^(3)-10y^(3)(2x+y)^(2)+5y^(4)(2x+y)-y^(5)

(10)/(x+y)+(2)/(x-y)=4,(15)/(x+y)-(5)/(x-y)=-2

Find the values of (x+y ) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 5x - 2y = 4 , x + 8y = 26

Solve the following system of equations by matrix method : 5x+7y+2=0 4x+6y+3=0 5x+2y=3 3x+2y=5 3x+4y-5=0 x-y+3=0 3x+y=19 3x-y=23 3x+7y=4 x+2y=-1 3x+y=7 5x+3y=12