" If "z=x+iy" then the equation "|(2z-i)/(z+1)|=m" does not represent a circle when "

If z=x+i y , then the equation |(2z-i)/(z+1)|=m does not represents a circle, when m is (a) 1/2 (b). 1 (c). 2 (d). 3

If z=x+i y , then the equation |(2z-i)/(z+1)|=m does not represents a circle, when m is (a) 1/2 (b). 1 (c). 2 (d). 3

The equation |((1+i)z-2)/((1+i)z+4)|=k does not represent a circle when k is

If z=x+i y , then he equation |(2z-i)/(z+1)|=m represents a circle, then m can be (a) 1/2 b. 1 c. 2 d. 3

If z=x+iy, then he equation |(2z-i)/(z+1)|=m represents a circle,then m can be (1)/(2) b.1 c.2d.3

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, then the equation |(2z-i)/(z+1)|=k will be a straight line,where -

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+i)))=m represents a circle, then m can be

If z=x+iy , then the equation |z+1|=|z-1| represents