Let `f: R->R` be such that `f(1)=3a n df^(prime)(1)=6.` Then `lim_(x->0)((f(1+x))/(f(1)))^(1//x)=` (a)`1` (b) `e^(1/2)` (c) `e^2` (d) `e^3`

Let f:RtoR be such that f(1)=3 and f'(1)=6 . Then lim_(xto0)[(f(1+x))/(f(1))]^(1//x) equals

Let f : R to R be such that f (1) = 3 and f'(1) = 6. Then, lim_( x to 0) [(f(1+x))/(f(1))]^(1//x) equals

A function f:R rarr R is such that f(1)=3 and f'(1)=6. Then lim_(x rarr0)[(f(1+x))/(f(1))]^(1/x)=

Let R rarr R be such that f(1)=3 and *f'(1)=6. then lim_(x rarr0)((f(1+x))/(f(1))) equal : (1)1(2)e^((1)/(2))(3)e^(2) (4) e^(3)

Let f:Rvec R be such that f(a)=1,f'(a)=2 Then (lim_(x))_(x0)((f^(2)(a+x))/(f(a)))^(1/x) is a e^(2) b.e^(4) c.e^(-4)d.1/e

Let g^(prime)(x)>0a n df^(prime)(x)<0AAx in Rdot Then (f(x+1))>g(f(x-1)) f(g(x-1))>f(g(x+1)) g(f(x+1))

Let f : R to R be a differentiable function satisfying f'(3) + f'(2) = 0 , Then lim_(x to 0) ((1+f(3+x)-f(3))/(1+f(2-x)-f(2)))^(1/x) is equal to