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5.x^(2)-x=156...

5.x^(2)-x=156

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If x^(2)+y^(2)=156 and x-y=12 , then xy=?

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The equations of the directrices of 16x^(2) + 25y^(2) - 96x - 100y - 156 = 0 are

Solve: 4x+(6)/(y)=156x-(8)/(y)=14 and hence find p if y=px-2

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Suppose 1,2,4,6 are roots of x^(5)+ax^(3)+bx^(2)=c find value of [c+156]=?