Evaluate :
`2.bar(5)-0.bar(35)`

Explanation

To evaluate \( 2.\overline{5} - 0.\overline{35} \), we first need to understand what these repeating decimals mean.

### Step 1: Convert \( 2.\overline{5} \) to a fraction
Let \( x = 2.\overline{5} \).

To eliminate the repeating decimal, we can multiply \( x \) by 10:
\[ 10x = 25.\overline{5} \]

Now, we subtract the original \( x \) from this equation:
\[ 10x - x = 25.\overline{5} - 2.\overline{5} \]
\[ 9x = 25 - 2 \]
\[ 9x = 23 \]
\[ x = \frac{23}{9} \]

### Step 2: Convert \( 0.\overline{35} \) to a fraction
Let \( y = 0.\overline{35} \).

Again, multiply \( y \) by 100 to eliminate the repeating decimal:
\[ 100y = 35.\overline{35} \]

Now, subtract the original \( y \):
\[ 100y - y = 35.\overline{35} - 0.\overline{35} \]
\[ 99y = 35 \]
\[ y = \frac{35}{99} \]

### Step 3: Subtract the two fractions
Now we need to evaluate \( \frac{23}{9} - \frac{35}{99} \).

To subtract these fractions, we need a common denominator. The least common multiple of 9 and 99 is 99.

Convert \( \frac{23}{9} \) to have a denominator of 99:
\[ \frac{23}{9} = \frac{23 \times 11}{9 \times 11} = \frac{253}{99} \]

Now we can subtract:
\[ \frac{253}{99} - \frac{35}{99} = \frac{253 - 35}{99} = \frac{218}{99} \]

### Step 4: Simplify the fraction if possible
Now we check if \( \frac{218}{99} \) can be simplified. The greatest common divisor (GCD) of 218 and 99 is 1, so this fraction is already in its simplest form.

Thus, the final answer is:
\[ \frac{218}{99} \]