Home
Class 9
MATHS
The give figure shows a square ABCD and ...

The give figure shows a square ABCD and an equilayeral teiangle APB. Calculate :
`{:((1)angleAOB,(ii)angleBPC),((iii)anglePCD,(iv)"reflex"angleAPC):}`

A

`(i)75^(@)" "(ii)75^(@)" "(ii)15^(@)" "(iv)225^(@)`

B

`(i)55^(@)" "(ii)65^(@)" "(ii)35^(@)" "(iv)215^(@)`

C

`(i)65^(@)" "(ii)35^(@)" "(ii)45^(@)" "(iv)220^(@)`

D

`(i)45^(@)" "(ii)65^(@)" "(ii)35^(@)" "(iv)125^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • QUADRILATERALS

    NAGEEN PRAKASHAN|Exercise Exercise 8b|15 Videos
  • QUADRILATERALS

    NAGEEN PRAKASHAN|Exercise Revision Exercise (very Short Answer Questions)|10 Videos
  • QUADRILATERALS

    NAGEEN PRAKASHAN|Exercise Problems From NCERT/exemplar|11 Videos
  • PROBABILITY

    NAGEEN PRAKASHAN|Exercise Revision Exercise (very Short Answer /short Answer Questions)|10 Videos
  • STATISTICS

    NAGEEN PRAKASHAN|Exercise Revision Exercise|10 Videos

Similar Questions

Explore conceptually related problems

The given figure shows a square ABCD and an equilateral triangle ABP Calculate

The given figure shows a square ABCD and an equilateral triangle ABP Calculate:

The given figure shows a square ABCD and an equilateral triangle ABP.Calculate: /_AOB,/_BPC

The adjoining figure shows a square ABCD and an equilateral triangle DEC. Prove that : (i) angleADE=angleBCE=30^(@) (ii) Delta cong DeltaBCE

The following figure shows a square ABCD and an equilateral triangle DCE. Prove that : (i) angleADE=angleBCE=150^(@) (ii) DeltaADE cong DeltaBCE (iii) AE = BE

In the adjoining figure, ABCD is a square and PAB is an equilateral triangle. Find : (i) angleAPD (ii) anglePDC (iii) angleDPC (iv) Prove that DP = CP

In the adjoining figure , ABCD is a parallelogram in which angleCAD=40^@, angleBAC=35^@ and angleCOD=65^@ Calculate : (i) angleABD (ii) angleBDC (iii) angleACB (iv) angleCBD

\n the following diagrams, ABCD is a square and APB is an equilateral triangle.In each case ,(1) Prove that : triangle APD = triangle BPC (ii) Find the angles of triangle DPC.

In the figure, P is a point in the interior of a parallelogram ABCD. Show that (i) ar (triangleAPB)+ar(trianglePCD=1/2ar(ABCD) (ii) ar (triangleAPD)+ar(trianglePBC)=ar(triangleAPB)+ar(trianglePCD)

In the given figure, ABCD is a square and anglePQR=90^(@).If PB=QC=DR, prove that. (i) QB = RC (ii) PQ = QR (iii) angleQPR=45^(@)

NAGEEN PRAKASHAN-QUADRILATERALS-Exercise 8a
  1. In the given figure, ABCD is a square and anglePQR=90^(@).If PB=QC=DR,...

    Text Solution

    |

  2. In a square ABCD, diagonals meet at O. P is point on BC such that OB =...

    Text Solution

    |

  3. The give figure shows a square ABCD and an equilayeral teiangle APB. C...

    Text Solution

    |

  4. In the given figure, ABCD is a rohombus with A=67^(@). If DEC is an eq...

    Text Solution

    |

  5. If the adjacent angles of a parallelogram are in the ratio 1/3:1/2. Fi...

    Text Solution

    |

  6. Prove that the sum of two consecutive angles of a parallelogram is 180...

    Text Solution

    |

  7. One angle of a parallelogram is 60^(@). Find its remaining angles.

    Text Solution

    |

  8. One diagonal of a parallelogram biscets its one of the angles. Show th...

    Text Solution

    |

  9. The opposite angles of a parallelogram are (3x-2)^(@)and(150-x)^(@). F...

    Text Solution

    |

  10. In the adjoining figure, ABCD is a parallelogram. If angleABC=125^(@),...

    Text Solution

    |

  11. In a parallelogram, one angleis twice of its consecutiv angle. Find al...

    Text Solution

    |

  12. In a parallelogram ABCD, AX and CY are the bisectors of angleAandangle...

    Text Solution

    |

  13. In a parallelogram PQRS, PX and QY are the perpendiculars drawn from P...

    Text Solution

    |

  14. In a parallelogram ABCD, the bisector of angleA bisects the line Bcat ...

    Text Solution

    |

  15. In a parallelogram ABCD, angleBCD=60^(@) If the bisectors AP and BP of...

    Text Solution

    |

  16. In the adjoining figure, DeltaPQR is formed by the sides PQ, QR and RP...

    Text Solution

    |

  17. X and Y are the mid-points of the opposite sides AB and DC of a parall...

    Text Solution

    |

  18. Two points X and Y lie on the diagonal BD of a parallelogram ABCD such...

    Text Solution

    |

  19. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

    Text Solution

    |

  20. AB and CD are two parallel lines and a transversal 'l' intersects thes...

    Text Solution

    |