In a quadrilateral ABCD the linesegment bisecting `angleC and angleD` meet at E. Prove that `angleA+angleB=2angleCED.`

In a quadrilateral ABCD, AO and BO are the bisectors of angleA and angleB respectively. Prove that angleAOB=1/2(angleC+angleD).

If bisectors of angleA and angleB of a quadrilateral ABCD intersect each other at P, of angleB and angleC at Q, of angleC and angleD at R and of angleD and angleA at S, then PQRS is a

In a quadrilateral ABCD, angleA + angleC = 180^(@) , then angleB + angleD is equal to

Bisectors of angles A and D of a quadrilateral ABCD meet at P. Prove that angleAPD=(1)/(2)(angleB+angleC)

In the adjoining figure, AB gt AC and the angle bisectors of angleB and angleC meet at point P. Prove that PB gt PC .

In a quadrilateral ABCD angleA+angleC is 2 times angleB+angleD . If angleA=140^(@)angle D=60^(@) , then angleB =

In triangleABC,angleA=40^(@) if bisector of angleB and angleC meets at O then prove that angleBOC=110^(@)

In DeltaABC exterior angle bisectors of angleB and angleC meets at point P if angleBAC=80^(@) then find angleBPC .