1000 families with 2 children were selected randomly and the following data were recorded.
`|{:("Number of boys in a family"," 0 1 2"),("Number of families"," 140 560 300"):}|`
If a family is chosen at random, find the probability that it has (i) no boy (ii) one boy (iii) two boys (iv) at least one boy (v) at most one boy.

Explanation

(i) No of families having no boy child = 140
`therefore" P(getting a family with no child)"=("number of families with no boy child")/("total number of families")`
`=(140)/(1000)=(7)/(50)`
(ii) Number of families having one boy child = 560
`therefore" P(getting a family with one boy child)"=(560)/(1000)=(14)/(25)`
(iii) Number of families having two boy children = 300
`therefore" P(getting a family with two boy children)"= (300)/(1000)=(3)/(10)`
(iv) Number of families having at least one boy child = 560 + 300 = 860
`therefore" P(getting a families having at least one boy child)"=(860)/(1000)=0.86`
(v) Number of families having at most one boy child = 140 + 560 = 700
`therefore" P(getting a family with at most one boy child)"=(700)/(1000)=0.7`