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A bag contains 5 red balls and some blue...

A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, find the number of blue balls in the bag.

A

`10`

B

`11`

C

`13`

D

`12`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the number of blue balls in the bag, given that the probability of drawing a blue ball is double that of drawing a red ball. ### Step-by-Step Solution: 1. **Identify the Variables**: - Let the number of blue balls be \( b \). - The number of red balls is given as \( 5 \). 2. **Calculate the Total Number of Balls**: - The total number of balls in the bag is \( 5 + b \). 3. **Find the Probability of Drawing a Red Ball**: - The probability of drawing a red ball is given by the formula: \[ P(\text{Red}) = \frac{\text{Number of Red Balls}}{\text{Total Number of Balls}} = \frac{5}{5 + b} \] 4. **Find the Probability of Drawing a Blue Ball**: - The probability of drawing a blue ball is given by: \[ P(\text{Blue}) = \frac{\text{Number of Blue Balls}}{\text{Total Number of Balls}} = \frac{b}{5 + b} \] 5. **Set Up the Relationship Between the Probabilities**: - According to the problem, the probability of drawing a blue ball is double that of drawing a red ball: \[ P(\text{Blue}) = 2 \times P(\text{Red}) \] - Substituting the probabilities we found: \[ \frac{b}{5 + b} = 2 \times \frac{5}{5 + b} \] 6. **Simplify the Equation**: - Multiply both sides by \( 5 + b \) to eliminate the denominator: \[ b = 2 \times 5 \] - This simplifies to: \[ b = 10 \] 7. **Conclusion**: - Therefore, the number of blue balls in the bag is \( 10 \). ### Final Answer: The number of blue balls in the bag is \( 10 \). ---

To solve the problem, we need to find the number of blue balls in the bag, given that the probability of drawing a blue ball is double that of drawing a red ball. ### Step-by-Step Solution: 1. **Identify the Variables**: - Let the number of blue balls be \( b \). - The number of red balls is given as \( 5 \). ...
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